If f is continuous on the closed interval [a,b]. f(a)≠f(b), and k is any number between f(a) and f(b), then there is at least one number c in [a,b] such that f(c)=k
Back
y=sinx
Front
dy/dx= cosx × d(x)/dx
Back
Continuity at a Point
Front
Given that f(x) at x=a
I. f(a) must exist
II. Lim f(x) x→a exists
III. Lim f(x) x→a = f(a)
Back
Speed Increasing
Front
v(t) and a(t) have the same sign
Back
Critical Number
Front
Let f be defined at c. If f'(c)= 0 or if f is not differentiable at c, then c is a critical number
Back
a) particle at rest
b) particle to right/up
c) particle to left/down
Front
a) v(t)= 0
b) v(t) > 0
c) v(t) < 0
Back
vertical asymptote
Front
Non-removable discontinuities
Back
y= tanx
Front
y'= sec^2(x)
Back
Instantaneous Velocity (Velocity= Speed and Direction)
Front
Derivative of the position function
Back
y= a^u
(Constant to a Variable Power)
Front
y= lna × a^u × u'
Back
Hits the ground
Front
1) x(t)= 0
2) Plug that t into position function
Back
y= arccosu
Front
Back
Average Function
Front
The change in position/The change in time
Back
Trig Limit (cosx)
Front
Lim θ→0 1-cosθ/θ = 0
Back
y= secx
Front
y'= secxtanx
Back
Unit Circle
Front
Back
y= arccscu
Front
Back
Trig Table
Front
Back
y= log∨a(u)
Front
y'= (1/lna × U) × U'
Back
y= arcsinu
Front
Back
Section 2
(27 cards)
The graph of f(x) is concave up
Front
f''(x) > 0
Back
∫ 1/x dx
Front
ln |x| +c
Back
Fundamental Thm of Calculus
Front
Back
∫ sin du
Front
-cos u +c
Back
Guidelines for Finding Extreme on a Closed Interval
Front
1) Find the critical numbers of f in (a,b)
2) Evaluate f at each critical number of [a,b]
3) Evaluate f at each endpoint of [a,b]
4) The least of these values is the minimum and the greatest is the maximum
Back
Graph of f(x) is decreasing
Front
f'(x) < 0
Back
∫ a^u du
Front
Back
Point of inflection
Front
The graph of f(x) changes concavity, f''(x)=0 or undefined, f''(x) changes sign
Back
∫ dx
Front
x+c
Back
The graph of f(x) is concave down
Front
f''(x) < 0
Back
∫ cos u du
Front
sinu +c
Back
Horizontal Asymptotes
Front
y= lim f(x)
x → ± ∞
Back
Second Fundamental Theorem of Calculus
Front
Back
∫ x^n dx
Front
x^(n+1)/(n+1) + c; n≠-1
Back
Average Value of a Function
Front
Back
∫ secutanu du
Front
sec u +c
Back
Max
Front
f'(x) goes from + to -
Back
Rolle's Thm
Front
Let f be continuous on the closed interval [a,b] and differentiable on the open interval (a,b). If f(a)=f(b), then there is at least one number c in (a,b) such that f'(c)=0
Back
Graph of f(x) is increasing
Front
f'(x) > 0
Back
Second Derivative Test
Front
1) Find critical #s from First Derivative
2) Take f'(x)
3) Plug points into f''(x)
4) f''(x) > 0 Min pt
f''(x) < 0 Max pt
f''(x) = 0 Test fails
Back
∫ csc^2 u du
Front
-cot u + c
Back
∫ cscucotu du
Front
-csc u+ c
Back
Mean Value Thm
Front
If f is continuous on [a,b] and differentiable on the open interval (a,b) then there exists a number c such that
f'(c)= f(b)-f(a)/b-a
Back
∫ e^u du
Front
e^u +c
Back
Min
Front
f'(x) goes from - to +
Back
∫ sec^2 u du
Front
tan u+ c
Back
Trig Identities
Front
1). sin^2x+ cos^2x= 1
a) ÷sin^2x
b) ÷cos^2x
2) sin2x= 2sinxcosx
3) cos2x= cos^2x-sin^2x
OR = 1-2sin^2x
OR = 2cos^2x-1