Logo

Go on. Explore!

lvl 0 • 0 xp

lvl 1

HomeMarketDecksInterests
projectile motion - ap physics

projectile motion - ap physics

memorize.aimemorize.ai (lvl 286)
Star 0%
Star 0%
Star 0%
Star 0%
Star 0%
(0)
(0)
(0)
27 cards
()
Section 1

Preview this deck

angled launch on elevated surface: finding time

Front

1 / 27

Physics
Star 0%
Star 0%
Star 0%
Star 0%
Star 0%

0.0

0 reviews

5
0
4
0
3
0
2
0
1
0

Active users

0

All-time users

0

Favorites

0

Last updated

7 years ago

Date created

Mar 1, 2020

Cards (27)

Section 1

(27 cards)

angled launch on elevated surface: finding time

Front

y = y₀ + vy₀t + 1/2gt² *y = 0 *y₀ = height of cliff *g = -9.8 * vy₀ = vsinθ *will need to use quadratic/factor

Back

angled launch: calculating maximum height

Front

*find vx and vy vfy² = v₀y² + 2ady (dy is the maximum height) *plug all numbers in

Back

range

Front

horizontal distance traveled by projectile

Back

maximum height

Front

-height of projectile when vertical velocity is 0 -only has velocity horizontal component

Back

vx VS v (velocities)

Front

*whatever the velocity is given to you: -if it is a horizontal launch the number = vx -if it is an angled launch the number = v

Back

kinematic equations

Front

x = vt v² = v₀² + 2ax x = v₀t + 1/2at² v = v₀ +at x = (v + v₀/2)t

Back

horizontal launch: velocity in the y direction

Front

vy = vy₀ + ayt

Back

finding final speed of the object

Front

v = √vx² + vy²

Back

horizontal launch: finding the range

Front

R = vx * t

Back

angled launch: finding vx

Front

vx = vcosθ

Back

angled launch: calculating time

Front

vfy = v₀y + ayt *plug the number found for vy into both vfy and v₀y, making vfy negative *plug in acceleration, making it negative

Back

angled launch on elevated surface: calculating speed

Front

vy = vy₀ + ayt *v = √vx² + vy² *vy₀ = vsinθ *a = -9.8

Back

angled launch on elevated surface: calculating angle

Front

inverse tan = (vy/vx)

Back

acceleration in the y direction

Front

9.8

Back

angled launch: finding vy

Front

vy = vsinθ

Back

angled launch

Front

-flat surface with no elevation -launched at an angle

Back

horizontal launch

Front

-throwing something down from an elevated surface -no angles involved

Back

quadratic formula

Front

Back

horizontal launch: finding height

Front

dy = vy₀t +1/2ayt² h = 1/2at²

Back

finding angle of the ball

Front

inverse tan = (vy/vx)

Back

acceleration in the x direction

Front

0

Back

air resistance

Front

-blowing in same direction as initial movement = distance travelled will increase -blowing in opposite direction as initial movement = distance travelled decreases

Back

trajectory

Front

path through spacce

Back

what is vx?

Front

-initial speed of the object -never changes

Back

angled launch: calculating range

Front

dx = vx * t *find vx and vy *plug vy into (vfy = v₀y + at) *plug the number found for vy into both vfy and v₀y, making vfy negative *make acceleration negative *solve for time *plug vx and time in to solve for range

Back

angled launch on elevated surface: calculating range

Front

R = vx * t

Back

projectile

Front

object being shot through the air

Back