independently controlled by the sonographic instrument
Not related
Back
Frequency units
Front
Hertz (Hz)
Back
increasing density
Front
decreases the speed of sound in tissues
Back
Human hearing
Front
20 Hz to 20,000 Hz
Back
Continuous Wave vs Pulsed ultrasound
Front
Ultrasound in which cycles repeat indefinitely
Not used
Pulses: Separated in time with gaps of no ultrasound
Back
The stiffer the media , the ___ sound propagates
Front
faster
Back
Stiffness
Front
resistance of a material to compression
EX:
Sponge=low stiffness/high compressibility/low sound speeds
rock=high stiffness/low compressibility/high sound speeds
Back
Pulse Duration
Front
Time it takes for 1 pulse to occur
PD(us)=NcxT(us)
Back
Another word for sound traveling
Front
Propagates
Back
propagation speed is determined by
Front
the medium primarily its stiffness (hardness)
Back
When the pressure is higher, the medium is
Front
more dense
Back
fundamental frequency
Front
original frequency
Back
Density
Front
mass/volume
Back
Average propagation speed in soft tissues
Front
1540 m/s
or
1.5 mm/us
Back
Acoustic Variables
Front
1. Pressure 2. Density 3. Temperature 4. Particle Motion
Back
Wavelength
Front
-Length of space that one cycle takes up
-Distance from the beginning to the end of one cycle
-Cycle length
-mm
Y(mm)=c(mm/us)/f(Mhz)
c=1.54 mm/us
Back
Bone propagation speed is ___ than soft tissue because ____
Front
speeds are higher because more solid
Back
Nonlinear propagation
Front
propagation in which speed depends on pressure and the shape of the wave changes
Back
the higher the temp of a solid or liquid, the ___ the propagation of sound waves
Front
faster
Back
Pressure
Front
Cyclic variations of mechanical force; sine wave
Back
Why is propagation speed important?
Front
sonographic instruments use it to accurately locate echoes on the display
Back
Frequency
Front
-measurement of how often something happens
-count of how many complete cycles of pressure occurs in 1 sec
f=#of cycles in 1 sec
Back
PRP/PRF equation
Front
PRP (ms) = 1/PRF(kHz)
Back
PRF
Front
# of pulses in 1 sec
Units: Kilohertz (kHz)
Back
Lung tissue propagation speed is ____ than soft tissue because ____
Front
much lower speed because lung has air
Back
Period
Front
-the time that it takes a complete cycle or wave oscillation to occur
-T(us)=1/f(Mhz)
Back
Rarefraction
Front
Regions of low pressure and density
Back
Sound requires what to travel?
Front
Medium
cannot be vacuum
Back
Transverse Wave
Front
motion perpendicular to the direction of wave travel.
EX: light, radio, and microwaves
Electromagnetic waves are transverse waves of electric and magnetic fields that involve no particle motion
Back
Why is the use of harmonics important?
Front
Harmonic frequency echoes improves the quality of sonographic images
Back
PRP related to PRF
Front
Reciprocal
PRP (ms) = 1/PRF(kHz)
When more pulses occur in a sec, the time between them decreases
Back
Period equation
Front
T(us)=1/f(Mhz)
Back
Longitudinal Wave
Front
back and forth particle motion is parallel to the direction of wav travel
Ex: Sound waves
Back
PRP
Front
time from the beginning of one pulse to the beginning of the next pulse
Units: ms
Back
PRF increases while PRP
Front
decreases
Back
Ultrasound
Front
Sound waves with frequencies above 20,000 Hz.
Back
high temp ____ the density of medium
Front
lower
Back
When the pressure is lower, the medium is
Front
less dense
Back
Propagation speeds are highest in ____ and lowest in _____
Front
highest in solids
lowest in gases
Back
If frequency increases, the wavelength will
Front
decrease
Back
If frequency increases, period
Front
decreases
Back
Sound is described by
Front
frequency
period
wavelength
Propagation speed
Amplitude
Intensity
Back
Harmonics
Front
The even and odd multiples
Back
Wave
Front
Traveling variation in one or more quantities
Back
A cycle is
Front
one complete variation in pressure or other acoustic variable
Back
Sound is a
Front
-Mechanical compressional wave
-Longitudinal wave
-Traveling variation of acoustic variables
Back
Infrasound
Front
Sound waves with frequencies below 20 Hz.
Back
Why is PRF important?
Front
determines how quickly images are generated
Back
Wavelength equation
Front
λ(mm)=c(mm/us)/f(MHz)
Back
Compression
Front
Regions of high pressure and density
Back
Section 2
(50 cards)
DF units
Front
none
Decimal or percentage
Back
Why is Attenuation important?
Front
1. Limits imaging depth
2.its weakening effects on the image must be compensated by the diagnostic instrument.
Back
Longer the SPL, ______ the attenuation
Front
the greater the attenuation
Back
If attenuation coefficient increases, attenuation ________
Front
increase
Back
PD decreases if the number of cycles in a pulse is ___
Front
decreased or frequency is increased
Back
PRF determines
Front
# of scan lines produced pr second and #of images produced pr second (FR)
Back
SPL equation:
Front
SPL(mm)=Nc x λ(mm)
Back
Spatial Pulse Length
Front
the length of a pulse
Back
If the attenuation coefficient increases, attenuation
Front
increases
a=acxL
Back
Impedance
Front
determines how much of an incident sound wave is reflected back into the first medium and how much is transmitted into the second medium
Units:Rayls
z(rayls) = p(kg/m^3) x c(m/s)
Back
Attenuation
Front
weakening of sound while it propagates
Units: Decibels
a(dB)=1/2(dB/cm-MHz) x f(MHz) x L (cm)
a(dB)=ac(dB/cm)xL(cm)
attenuation=absorption + scattering
Back
Energy
Front
the ability to do work
Ex:Heat, light, x-rays, microwaves, mechanical motion
Back
Impendance increases if
Front
density increases
or
Propagation increases
z=p x c
Back
If the path length increases ... attenuation ...
Front
increases
Back
PD equation
Front
PD(us)=NcxT(us)
Back
Sonographic pulses are typically ____ or ____ cycles long.
Front
2 or 3 cycles
Back
Amplitude
Front
The measure of how far the particles in the medium move away from their normal rest position.
Max-normal=Amplitude
Back
If PRF increases, then DF
Front
increases
Back
Intensity and Amplitude
Front
I=Amplitude^2
Back
Absorption
Front
conversion of sound to heat
Back
If the frequency increases, Attenuation ____
Front
Increases
a=1/2 x f x L
Back
What are strength indicators of sound
Front
Intensity and amplitude
Back
attenuation coefficient
Front
Attenuation that occurs with each centimeter
Units: dB/cm
a=ac(dB/cm) x L(cm)
Back
If amplitude is halved, intensity is
Front
quartered
Back
Higher/increasing PRF ____ the DF because
Front
increases DF because there is less listening time between pulses
Back
Perpendicular incidence
Front
sound direction that is perpendicular to the boundary between media
Back
Bandwith
Front
The range of frequencies with a given band, in particular that is used for transmitting a signal.
Back
intensity reflection coefficient (IRC)
Front
IRC=Ir/Ii
[(Z2-Z1)/(Z2+Z1)]^2
Reflected/Incident
Back
Intensity transmitted coefficient (ITC)
Front
ITC=It/Ii
1-IRC
Transmitted/incident
Back
The intensities of the reflected sound and the transmitted sound depend on the
Front
incident intensity at the boundary and the impedances of the media on either side of the boundary
Back
Longer pulses ___ the DF because ____
Front
increase DF because the sound is on more of the time
Back
Duty Factor
Front
Fraction of time that pulsed ultrasound is on
Back
What is the reciprocal of bandwidth called?
Front
quality factor (Q)
Back
Sum of the reflected and transmitted intensities must equal
Front
1
Back
Attenuation is higher in ___ than soft tissue
Front
lung and bones
Back
The shorter the pulse (few # of cycles) the ___ the number of frequencies it contains (___ bandwidth)
Front
Shorter the pulse, higher number of frequencies, Broader bandwidth
Back
DF equation
Front
DF = PD(us)/PRP(us)
Back
Shorter SPL's create images with...
A) less detail
B) does not change
C) greater detail
Front
greater detail improves resolution
Back
Typical DF for sonography is
Front
range of 0.1% and 1.0%
Back
What is the dominant factor that contributes to attenuation of ultrasound in soft tissue?
Front
Absorption
Back
The farther the sound travels, the ________ the attenuation
Front
greater
Back
Power
Front
-rate at which energy is transferred from one part of a system to another
-energy transferred/the time rquired to transfer energy
Units:Watts (W)
Back
fractional bandwidth
Front
bandwidth divided by operating frequency
-Unitless
Back
attenuation increases, frequency
Front
increases
a=1/2 x f x L
Back
Sound is a form of what kind of energy?
Front
mechanical energy
Back
Shorter pulses ____ the quality of sonographic images
Front
improve!
Back
The greater the difference between the impedances...
Front
the stronger the echo
Back
Intensity
Front
rate at which energy passes through a unit area
I(mW/cm^2)=P(mW)/A(cm^2)
Back
If the amplitude is doubled, the intensity is
Front
quadrupled
Back
The greater the similarity of the impedances...
Front
the weaker the echo
Back
Section 3
(50 cards)
Why is scattering beneficial in ultrasound?
Front
Need to see the "fog" and not mirror the transducer
Back
propagation speed of 2 mediums and transmitted and incident angle
Front
If c1<c2 then 0i<0t
c1>c2 then 0i>0t
Back
Sound is a traveling variation in quantities called
Front
acoustic variables
Back
If IRC increases, the ITC
Front
decreases
Back
Speckle
Front
form of acoustic noise in sono imaging
Back
lower freq = ____ sensitivity
Front
better sensitivity because more penetration
Back
Nonlinear propagation means that __________.
Front
propagation speed depends on pressure, the waveform changes shape as it travels and harmonics to be generated
Back
Scattering
Front
redirection of sound in many directions by rough surfaces or by heterogeneous media such as blood
Back
Attenuation is the reduction in ___ and ___ as a wave travels through a medium
Front
Amplitude and intensity
Back
A wave is a traveling variation in quantities called
Front
wave variables
Back
the DF for a pulse ultrasound is
Front
always less than 1
Back
Refraction
Front
Change in direction of sound when it crosses a boundary
Back
With perpendicular incidence, two media ______ and the incident _______ must be known to calculate the reflected intensity.
Front
impedances, intensity
Back
range equation:
Front
d(mm)= 1/2(c x t)
c=1.54
t=13us
or
t(us)/13(us/cm)= d(cm)
Back
Under what 2 conditions does refraction not occur?
Front
1.perpendicular incidence
2. equal media propagation speeds
Back
Specular reflection
Front
Mirror-like reflection
smooth and flat boundary
Back
The greater the elasticity, the ___ the velocity
Front
slower
velocity= 1/elasticity
Back
2 requirements for refraction to occur
Front
oblique incidence
different propagation speed on either side of the boundary
Back
To position the echoes properly on the display , what 2 items of information are required
Front
1. direction from which the echo came
2.the distance to the reflector or scatterer where the echo was produced
Back
the DF of a continuous wave sound is
Front
1 (100%)
Back
If the direction of sound changes when it crosses a boundary...
Front
the transmission angle is different from the incident angle
(Refraction)
Back
Sound Beam Sensitivity
Front
The ability of the sound beam to reach and display the weakest echoes
Back
Image depth also is referred to as
Front
penetration
Back
Perpendicular incidence
Front
incidence angle is 0
Back
Propagation speed equation
Front
c=square root(B(Bulk modulus)/p(density)
Back
The transmitted angle depends on
Front
propagation speeds in the media
Back
If you have a stronger echo ..
Front
less remains to travel into the second medium
Back
sound is a
Front
A mechanical longitudinal wave
Back
Greater amplitude, ___ PD
Front
longer
*No change in frequency
Back
SPL is the
Front
length of space that a pulse occupies while it travels
Back
If the media impedances are the same
Front
no echo because no sound is reflected at the boundary and all of it travels into the second medium as if there are no boundary
Back
13us/cm rule
Front
13 us time for very centi
Back
Attenuation is the weakening of sound caused by
Front
absorption , reflection, and scattering
Back
imaging depth decreases
Front
PRF increases
Back
Bulk modulus
Front
measure of stiffness of medium or resistance of medium to being compressed
Equation:
C=Square root of B/p(density)
Back
How to calculate transmitted angle
Front
Med 2/ Med 1 = ratio
Ratio x angle of incidence or refraction = transmitted
Back
Elasticity
Front
demonstrate by a return to the original shape when the pressure is lowered to its initial value
Back
Oblique incidence
Front
direction of travel of the incident ultrasound that is not perpendicular to the boundary between 2 mediums
Back
The incidence angle is always equals the
Front
reflection angle
0i=0r
Back
When ultrasound encounrers a boundary with perpendicular incidence, the ___ of tissues must be different to produce a reflection (echo)
Front
impedance
Back
Absorption can be greater than attenuation in a given medium at a given frequency(T/F)
Front
False
Atten=abs+scatt
Back
If the propagation speed through the second medium is greater than through the first medium, the transmission angle is ________.
Front
greater than the incident angle
(refraction)
Back
Incident angle is zero (Perpendicular) there is ____ refraction with 2 different propagation speeds of 2 media
Front
no refraction even though there may be different propagation speeds in the media
Back
Amplitude is the maximum _________ that occurs in an acoustic variable.
Front
variation
Back
Coupling medium
Front
provide good sound path from the transducer to the skin eliminating the thin layer of air that would reflect sound
Back
Incident angle
Front
the angle between the incident ray and the normal
Back
Elasticity depends on
Front
strength of the force and elastic properties of the object
Back
Backscatter
Front
sound scattered back in the direction from which it originally came
Back
What is a typical DF for sonography?
Front
0.1
Back
Oblique incidence
reflected sound...
Front
does not return to the transducer but travels off in some other direction
Back
Section 4
(14 cards)
The sonographer changes the PRF and PRP by changing the:
Front
scanning depth
Back
Each pulse to the Trx crystal produces
Front
3 to 5 cycles of sound energy
Back
What does not change as amplitude is increased?
Front
Frequency
*Tuning fork=No matter how hard you strike it, the frequency remains the same
Back
Amplitude of 3 cycle pulse
Front
transmitted amplitude is less than incident
reflection amplitude is less than transmitted and incident
Back
Increased medium density is caused by the maximum amplitude of sound energy that is generated.