Section 1

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beats are produced when

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Last updated

6 years ago

Date created

Mar 1, 2020

Cards (62)

Section 1

(50 cards)

beats are produced when

Front

two waves have different frequencies

Back

if you half the length of a string the frequency

Front

doubles

Back

/\ f

Front

width at half the amp

Back

find p

Front

mass / length

Back

sec to ms

Front

1 sec = 1000 ms

Back

damping time is

Front

the time it takes for the amplitude to decrease to half of its value

Back

cm to m

Front

x .01

Back

how does the pitch you hear from the pipe as it gets colder compare to the pitch you hear when the pipe is warm

Front

the pitch would get lower when it is colder - colder temp = slower speed of sound

Back

touch a string at (point)

Front

modes where have a node at (point) will survive -induce node at that (point)

Back

if you increase damping then the damping time

Front

decreases

Back

harmonic motion

Front

Back

what happens to the frequency of a 500 Hz piano string if its diameter is doubled with the material kept the same?

Front

if you double the diameter then you halve the frequency

Back

period

Front

time it takes for one oscillation to occur

Back

if you pluck a string at 1/3 the distance

Front

1st, 2nd, 4th, 5th, 7th non multiples of 3

Back

damping can be caused by

Front

friction

Back

force depends on length - keeping the tension the same

Front

Back

which mode requires more effort to sustain the oscillation: higher modes or the fundamental mode?

Front

higher modes

Back

You have a string that vibrates with a fundamental frequency of 600 Hz. If the tension was reduced to half of its former value, what is the new fundamental frequency?

Front

600/ sqrt 2 =

Back

node

Front

a point at which lines or pathways intersect or branch; a central or connecting point

Back

what happens to the pitch when the loudness is increased

Front

pitch stays the same

Back

if you decrease damping time the frequency width

Front

increases

Back

waves

Front

periodic repetitive motion (motion that repeats)

Back

how are pipes compared to strings

Front

pipes are similar to strings in the fact that they both go down in frequency -velocity of a string depends on thickness while pipe depends on temp

Back

hz to kilohertz

Front

x .001

Back

closed pipe

Front

f = V/4L

Back

how do the frequencies change when you make a pipe longer

Front

the frequency goes lower

Back

are the ends of pipe nodes or antinodes?

Front

nodes h

Back

A mass on a spring oscillates with a certain frequency f. What is the oscillation frequency if the spring is replaced with one that is four times weaker?

Front

new oscillation frequency is half as large

Back

what happens to pitch when frequency is increased?

Front

pitch will increase

Back

diameter affects freq of string and not pipe

Front

Back

if you pluck string at 1/5th distance

Front

1,2,3,4,6,7,8,9,11 all non multiples of 5

Back

antinode

Front

point of maximum displacement or amplitude

Back

frequency and period do not depend on amplitude

Front

Back

Circle the correct answers in the following sentence: Standing waves are the result of superposition of two sinusoidal waves of the same/different frequency and the same/different amplitude, traveling in the same/opposite directions.

Front

same - same - opposite

Back

What happens to the frequency of a piano string if you double the mass, keeping the same length and the same tension?

Front

It goes down by a factor of sqrt 2 = 1.414.

Back

if the force increases then displacement

Front

increases

Back

plucking a string at (point)

Front

all modes that have a node at that (point) will disappear

Back

if /\f increases the the damping time(T)

Front

decreases

Back

units for F=kx

Front

F = force k = spring constant x = displacement

Back

formula for period and frequency

Front

f=1/T

Back

pressure and relation to closed pipes

Front

- node pressure at open end - antinode pressure at close end

Back

What happens to the frequency of a 600 Hz piano string if you changed the tension from 200N to 50N?

Front

600 hz / f2 = sqrt 200 / sqrt 50

Back

frequency

Front

how many oscillations occur per second

Back

are resonant frequency and natural frequency the same thing?

Front

yes - resonant frequencys always resonates at the natural frequ

Back

what happens to the frequency you hear when you double the diameter of the pipe

Front

it gets slightly lower because the diameter changes the effective length of the pipe to be slightly longer

Back

if a wave has more friction then

Front

- it will have greater energy loss - damping time will decrease - /\f will increase - lower and wider curve

Back

1 gram =

Front

.001 kg

Back

if you pluck a string at the center which modes will be excited?

Front

1st, 3rd, 5th, 7th.... all odd modes

Back

open pipe equation

Front

f= v/2L

Back

equation to find phase change

Front

phase/360 = /\t/T

Back

Section 2

(12 cards)

A guitar string has a frequency of 440 Hz and a damping time of 2.1sec. (a) How many oscillations does the string make before the oscillation amplitude has decreased to half of the original value?

Front

440 x 2.1 = 924 oscillations

Back

If you pluck a guitar string at L/3 (one-third of the way from the end), which partials will be missing? Which is likely to be the strongest partial?

Front

3rd, 6th, 9th strongest: fundamental

Back

If the player now touches his finger lightly on the string at L/4 from one end, which modes of vibration (harmonics) survive? What pitch will be heard?

Front

4th, 12th, 8th.....etc

Back

a viola string of length 60 cm is tuned to g3(196 hz) what freq will the string produce when the length is reduced to 40 cm?

Front

60/40 = 1.5 1.5 x 196 = 294 hz

Back

if you want to double frequency what should you do to the mass?

Front

quadruple it

Back

for a string what happens to frequency if the diameter is doubled?

Front

it is halved 500hz becomes 250

Back

A certain spring has a frequency of 100 Hz when a 50g mass is hung from it. a) What would the frequency be if the mass were changed to 200g?

Front

200/50 = 4 sqrt 4 = 2 100/2 = 50hz

Back

How long does it take for the sound from a cymbal crash to reach a listener in the back of an auditorium, at a distance of 100m from the cymbal?

Front

v = /\x / t 344 = 100/x

Back

second overtone =

Front

3rd lowest from fundamental

Back

mass = tension = same

Front

Back

precentage change when there is a temperature change for pipes

Front

changed temp - normal temp / normal temp

Back

first overtone =

Front

2nd lowest from fundamental

Back