Y approaches (+ or -) infinity as x approaches c from left and right
Back
Minimum distance
Front
d^2 = (x2-x1)^2 + (y2-y1)^2; d^2 = Q; use derivative of Q; feasible domain; EVT
Back
Derivative of e^x
Front
e^x because e^h = 1 + h
Back
ln x/y
Front
ln x - ln y
Back
dy/dx arccos f(x)
Front
-f'(x)/ sqrt(1-f(x)^2)
Back
percent change
Front
change in y / f(x0) *100 [dy for estimate]
Back
dy/dx arcsin f(x)
Front
f'(x)/ sqrt(1-f(x)^2)
Back
Limits at Infinity
Front
As the limit approaches +/- infinity then k/bx^a=0 where a>0
Back
Optimization
Front
find primary and secondary equations; use derivative of the primary plug in secondary; feasible domain; EVT
Back
Average Function value
Front
integral from a to b of f(x) dx / b-a
Back
Rolle's Theorem
Front
Let f be continuous on [a,b] and differentiable on (a,b) and if f(a)=f(b) then there is at least one number c on (a,b) such that f'(c)=0 (If the slope of the secant is 0, the derivative must = 0 somewhere in the interval).
Back
Integration
Front
used to find the antiderivative (don't forget + C)
Back
Inscribed Area
Front
Back
ln e
Front
1
Back
First Derivative Test
Front
Used to determine where a function's graph has a min/max and is increasing or decreasing.
Back
dy/dx arctan f(x)
Front
f'(x) / f(x)^2 + 1
Back
e^(lnx)
Front
x
Back
Power rule
Front
d/dx[x^n]=nx^(n-1)
Back
concavity
Front
f is concave up when f' is increasing; f is concave down when f' is decreasing
if f(x) is continuous and differentiable, slope of tangent line equals slope of secant line at least once in the interval (a, b)
f '(c) = [f(b) - f(a)]/(b - a)
Back
Intermediate Value Theorem (IVT)
Front
If f is continuous on the closed interval [a,b] and k is any number between f(a) and f(b), then there is at least one number c in [a,b] such that f(c)=k
Back
dy/dx arccot f(x)
Front
-f'(x) / f(x)^2 + 1
Back
Chain rule
Front
d/dx f(g(x)) = f'(g(x)) g'(x)
Back
dy/dx arccsc f(x)
Front
-f'(x)/ |f(x)| * sqrt( f(x)^2 -1 )
Back
Constant Rule
Front
d/dx (c) = 0
Back
ln 1
Front
0
Back
Second Derivative Test
Front
Used to determine on what intervals a function is concave up/concave down and the points of inflections.
Back
Quotient Rule
Front
low d high - high d low / low^2
Back
Product rule
Front
1st d 2nd + 2nd d 1st
Back
ln xy
Front
ln(x)+ln(y)
Back
Points of Inflection
Front
If f has a tangent line at ( c, f(c) ) then c is a point of inflection if concavity of f is changing from up to down (vice versa)
Back
Extreme Value Theorem
Front
If f is continuous on [a,b] then f has an absolute maximum and an absolute minimum on [a,b]. The global extrema occur at critical points in the interval or at endpoints of the interval.
Back
ln e^x
Front
x
Back
To find total distance, integrate the ____________ function.
Front
velocity
Back
Secant Line
Front
a line that connects or passes through 2 points of a function's curve
Back
Constant Multiple Rule
Front
d/dx[cf(x)]=cf'(x)
Back
MVT for Integrals
Front
integral from a to b of f(x) dx / b-a = f(c)
Back
f is continuous at a number c if
Front
1. f(c) is defined
2. the limit as x approaches c exist
3. the limit as x approaches c = f(c)
Back
Removable discontinuity
Front
not continuous when x=c; a "hole"
Back
dy/dx logb f(x)
Front
f'(x)/ lnb * f(x)
Back
Area by definite integrals
Front
Back
Relative Change
Front
change in y / f(x0) [dy for estimate]
Back
Newton's Method
Front
x2=x1-f(x1)/f'(x1)
Back
Non-removable discontinuity
Front
y-values approach different values at x=c; a "jump"
Back
Section 2
(3 cards)
Net Change Theorem
Front
The change in y of the antiderivative can be found by finding the definite integral of the function
Back
First Fundamental Theorem of Calculus
Front
If f(x) is continuous on [a,b] then, g(x) =∫(a to b) f(t) dt, is continuous on [a,b] and it is differentiable on (a,b) and that, g'(x) = f(x)