Remember the equation for genotype frequency: p^2 + 2pq + q^2 = 1. If the disease is caused by a recessive allele (q), and if 1 out of 10,000 births is affected, then q2 = 1/10,000, so q = 1/100 = 0.01. Since q = 0.01, we have p = 0.99, because p + q = 1. The number of heterozygotes is then 2pq = 2(0.99)(0.01) ≈ 2(1)(0.01) = 0.02 = 2%.