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Chapter 6 ~ AP Physics

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Section 1

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At top of rollercoaster (upside down)

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Physics

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Date created

Mar 1, 2020

Cards (17)

Section 1

(17 cards)

At top of rollercoaster (upside down)

Front

V = √gr > feel more normal force (n) net force = mg + n = Fa n = (mVt²/r) - mg

Back

G

Front

6.67 x 10^-11

Back

Circular motion of an object connected to a string

Front

The reason for circular motion is the string > Fc = T * trig identity

Back

Force of attraction

Front

Fg = G x (m x M/d²) m = satellite M = planet d (or r) = distance between them (altitude + radius of planet) > free-fall acceleration at surface of planet g = GM/d² > d is distance to center of planet (r)

Back

speed in a circle

Front

V = 2πr/t (period of time for loop)

Back

T (Tension in string)

Front

reason for circular motion is string, that tension (= Fc) T = (mVt/r) + mg

Back

car on banked road, smooth (no friction) making turn

Front

Ft = (n)(trig identity) > normal force (n) component gives direction for turn > the reason for circular motion is road

Back

Car on rough road, making turn

Front

Fc = f static > without friction, the car would experience tangental velocity (keep going in straight line) > the static friction prevents from sliding off road > static friction force points toward center

Back

Fc (centripetal force)

Front

a force that acts on a body moving in a circular path and is directed toward the center around which the body is moving > a force that causes an object to move in a circle (F net) Fc = (m)(ac) = mVt²/r

Back

body is airborne

Front

g = Vt²/r > gravity keeps it moving in a circle

Back

orbital period

Front

T = 2π√r/g

Back

At bottom of rollercoaster (right-side up)

Front

net force = n - mg n more than w --> n = Fnet --> net force towards center mVt²/r = n - mg n = (mVt²/r) + mg

Back

orbital speed

Front

V = √GM/r > M is mass of planet (central body), so mass of satellite doesn't affect its own velocity > the orbital speed of a satellite around a planet depends on the radius of its orbit T = distance/V T = 2πr/(√GM/r)

Back

Vt (tangental velocity)

Front

is the linear speed of something moving along a circular path

Back

ω (angular speed)

Front

V = ωr Vt = 2πr/t (circumference over time of one revolution)

Back

f (frequency)

Front

1 / t V = 2πr/t

Back

ac (centripetal acceleration)

Front

acceleration of an object toward the center of a curved or circular path ac = V²/r a = ΔV/Δt a = T - w / m > an object wants to accelerate whenever it goes in a circle > net force producing the centripetal acceleration of uniform circular motion

Back