The instantaneous rate of change will equal the mean rate of change somewhere in the interval. Or, the tangent line will be parallel to the secant line.
Back
x+c
Front
Back
The position function OR s(t)
Front
Back
dy/dx
Front
Back
Fundamental Theorem of Calculus #1
Front
The definite integral of a rate of change is the total change in the original function.
Back
f is continuous at x=c if...
Front
Back
Critical Number
Front
If f'(c)=0 or does not exist, and c is in the domain of f, then c is a critical number. (Derivative is 0 or undefined)
Back
tan(x)+C
Front
Back
Alternative Definition of a Derivative
Front
f '(x) is the limit of the following difference quotient as x approaches c
Back
Exponential growth (use N= )
Front
Back
Formula for Disk Method
Front
Axis of rotation is a boundary of the region.
Back
L'Hopital's Rule
Front
Back
-csc(x)+C
Front
Back
Mean Value Theorem for integrals or the average value of a functions
Front
Back
-ln(cosx)+C = ln(secx)+C
Front
hint: tanu = sinu/cosu
Back
-sin(x)
Front
Back
Global Definition of a Derivative
Front
Back
sin(x)+C
Front
Back
f'(x)-g'(x)
Front
Back
uvw'+uv'w+u'vw
Front
Back
Point of inflection at x=k
Front
Back
sec(x)tan(x)
Front
Back
Combo Test for local extrema
Front
If f'(c) = 0 and f"(c)<0, there is a local max on f at x=c.
If f'(c) = 0 and f"(c)>0, there is a local min on f at x=c.
Back
Squeeze Theorem
Front
Back
Fundamental Theorem of Calculus #2
Front
Back
sec(x)+C
Front
Back
ln(cscx+cotx)+C = -ln(cscx-cotx)+C
Front
Back
ln(secx+tanx)+C = -ln(secx-tanx)+C
Front
Back
cos(x)
Front
Back
1
Front
Back
ln(x)+C
Front
Back
cf'(x)
Front
Back
nx^(n-1)
Front
Back
Intermediate Value Theorem
Front
If f is continuous on [a,b] and k is a number between f(a) and f(b), then there exists at least one number c such that f(c)=k
Back
Extreme Value Theorem
Front
If f is continuous on [a,b] then f has an absolute maximum and an absolute minimum on [a,b]. The global extrema occur at critical points in the interval or at endpoints of the interval.
Back
Area under a curve
Front
Back
Formula for Washer Method
Front
Axis of rotation is not a boundary of the region.
Back
0
Front
Back
-csc²(x)
Front
Back
f'(x)+g'(x)
Front
Back
1
Front
Back
Horizontal Asymptote
Front
Back
-cot(x)+C
Front
Back
ln(sinx)+C = -ln(cscx)+C
Front
Back
sec²(x)
Front
Back
-cos(x)+C
Front
Back
Rolle's Theorem
Front
Let f be continuous on [a,b] and differentiable on (a,b) and if f(a)=f(b) then there is at least one number c on (a,b) such that f'(c)=0 (If the slope of the secant is 0, the derivative must = 0 somewhere in the interval).
Back
First Derivative Test for local extrema
Front
Back
Section 2
(25 cards)
Opposite Antiderivatives
Front
Back
Greatest integer function
Front
D: (-∞,+∞)
R: (-∞,+∞)
Back
Constants in integrals
Front
Back
Sine function
Front
D: (-∞,+∞)
R: [-1,1]
Back
Square root function
Front
D: (0,+∞)
R: (0,+∞)
Back
Adding or subtracting antiderivatives
Front
Back
Identity function
Front
D: (-∞,+∞)
R: (-∞,+∞)
Back
Natural log function
Front
D: (0,+∞)
R: (-∞,+∞)
Back
Inverse Sine Antiderivative
Front
Back
Cosine function
Front
D: (-∞,+∞)
R: [-1,1]
Back
Exponential function
Front
D: (-∞,+∞)
R: (0,+∞)
Back
Reciprocal function
Front
D: (-∞,+∞) x can't be zero
R: (-∞,+∞) y can't be zero
Back
ln(a)*aⁿ+C
Front
Back
Given f'(x):
Is f continuous @ c?
Is there an inflection point on f @ C?
Front
This is a graph of f'(x). Since f'(C) exists, differentiability implies continuouity, so Yes.
Yes f' decreases on X<C so f''<0
f' increases on X>C so f''>0
A point of inflection happens on a sign change at f''
Back
Antiderivative of xⁿ
Front
Back
Antiderivative of f(x) from [a,b]
Front
Back
Inverse Tangent Antiderivative
Front
Back
Logistic function
Front
D: (-∞,+∞)
R: (0, 1)
Back
Absolute value function
Front
D: (-∞,+∞)
R: [0,+∞)
Back
Squaring function
Front
D: (-∞,+∞)
R: (o,+∞)
Back
Derivative of ln(u)
Front
Back
Derivative of eⁿ
Front
Back
Cubing function
Front
D: (-∞,+∞)
R: (-∞,+∞)
Back
Inverse Secant Antiderivative
Front
Back
Given f(x):
Is f continuous @ C
Is f' continuous @ C
Front
Yes lim+=lim-=f(c)
No, f'(c) doesn't exist because of cusp