AP Calculus AB Review

AP Calculus AB Review

memorize.aimemorize.ai (lvl 286)
Section 1

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Quotient rule of f(x)/g(x)

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Cards (73)

Section 1

(50 cards)

Quotient rule of f(x)/g(x)

Front

g(x)f'(x)-f(x)g'(x)/g(x)²

Back

a(t)=0

Front

v(t) not changing

Back

v(t)<0

Front

p(t) is moving left

Back

Mean Value Theorem

Front

if f(x) is continuous on [a,b] and differentiable on (a,b), there is at least one point (x=c) where f'(c)= F(b)-F(a)/b-a

Back

v(t) and a(t) has different signs

Front

speed of particle decreasing

Back

p(t), x(t), s(t)

Front

means position function

Back

∫csc²x dx

Front

-cotx+C

Back

v(t)>0

Front

p(t) is moving right

Back

d/dx(sinx)

Front

cosx

Back

d/dx(lnu)

Front

u'/u

Back

p'(t)

Front

v(t)= velocity

Back

limit as x approaches 0: 1-cosx/x

Front

0

Back

d/dx(cscx)

Front

-cscxcotx

Back

d/dx(a^u)

Front

a^u(lna)(u')

Back

∫k dx [k IS A CONSTANT]

Front

kx+C

Back

d/dx(secx)

Front

secxtanx

Back

v(t)=0

Front

p(t) is at rest or changing direction

Back

1st fundamental theorem of calculus

Front

(bounded by a to b) ∫f(x)dx= F(b)-F(a)

Back

limit as x approaches 0: sinx/x

Front

1

Back

∫sinx dx

Front

-cosx+C

Back

v(t) and a(t) has same signs

Front

speed of particle increasing

Back

Basic Derivative

Front

f(x^n)= nX^(n-1)

Back

∫secxtanx dx

Front

secx+C

Back

Limit Definition of Derivative

Front

limit (as h approaches 0)= F(x+h)-F(x)/h

Back

Alternate Definition of Derivative

Front

limit (as x approaches a number c)= f(x)-f(c)/x-c x≠c

Back

If f''(x)<0

Front

f(x) is concave down & f'(x) is decreasing

Back

Chain rule of f(x)^n

Front

nf(x)f'(x)

Back

Extreme Value Theorem

Front

if f(x) is continuous on [a,b], then f(x) has an absolute max or min on the interval

Back

∫(1/x)dx

Front

ln|x|+C

Back

d/dx(cotx)

Front

-csc²x

Back

Product rule of f(x)g(x)

Front

f'(x)g(x)+g'(x)f(x)

Back

Intermediate Value Theorem

Front

if f(x) is continuous on [a,b], then there will be a point x=c that lies in between [a,b]

Back

If f''(x)=0

Front

f(x) has a point of inflection & f'(x) has a max or min

Back

∫cscxcotx

Front

-cscx+C

Back

Rolle's Theorem

Front

if f(x) is continuous on [a,b] and differentiable on (a,b), and if f(a)=f(b), then there is at least one point (x=c) on (a,b) [DON'T INCLUDE END POINTS] where f'(c)=0

Back

a(t)>0

Front

v(t) increasing

Back

∫sec²x dx

Front

tanx+C

Back

If f''(x)>0

Front

f(x) is concave up & f'(x) is increasing

Back

If f'(x)>0

Front

f(x) is increasing

Back

d/dx(e^u)

Front

e^u(u')

Back

a(t)<0

Front

v(t) decreasing

Back

∫(e^kx)dx

Front

ekx/k +C

Back

∫cosx dx

Front

sinx+C

Back

If f'(x)=0

Front

there is a max or min on f(x) [number line test]

Back

∫(x^n)dx

Front

x^(n+1)∕(n+1) +C

Back

p''(t) or v'(t)

Front

a(t)= acceleration

Back

d/dx(tanx)

Front

sec²x

Back

d/dx(cosx)

Front

-sinx

Back

If f'(x)<0

Front

f(x) is decreasing

Back

Continuity Rule

Front

If the limit exists (aka left limit and right limit are equal), and the limit equals the function at that point.

Back

Section 2

(23 cards)

Cross section for volume: semicircle [A=1/2πs²]

Front

v= 1/2π∫[f(x)-g(x)]²dx

Back

position of particle at specific point

Front

p(x)= initial condition + ∫v(t)dt (bounds are initial condition and p(x))

Back

d/dx(cot⁻¹u)

Front

-u'/(1+u²)

Back

Volume (WASHER)

Front

V=π∫f(x)²-g(x)²dx

Back

Cross section for volume: isosceles triangle [A=1/2s²]

Front

v= 1/2∫[f(x)-g(x)]²dx

Back

Cross section for volume: equilateral triangle [A=√3/4s²]

Front

v= √3/4∫[f(x)-g(x)]²dx

Back

Area between curves

Front

A=∫f(x)-g(x) dx

Back

d/dx(sin⁻¹u)

Front

u'/√(1-u²)

Back

average value

Front

(1/(b-a))[∫f(x)dx] [BOUNDED BY A TO B]

Back

2nd fundamental theorem

Front

(bounded by 1 to x) d/dx[∫f(t)dt]= f(x)(x')

Back

∫du/(a²+u²)

Front

(1/a)(tan⁻¹u/a)+C

Back

d/dx(csc⁻¹u)

Front

u'/|u|√(u²-1)

Back

derivative of exponential growth equation: P(t)=Pe^kt

Front

dP/dt=kP

Back

Cross section for volume: square [A=s²]

Front

v=∫[f(x)-g(x)]²dx

Back

d/dx(cos⁻¹u)

Front

-u'/√(1-u²)

Back

total distance of particle

Front

∫|v(t)|dt

Back

∫du/√(a²-u²)

Front

(sin⁻¹u/a)+C

Back

d/dx(tan⁻¹u)

Front

u'/(1+u²)

Back

Volume (DISK)

Front

V=π∫f(x)²dx

Back

d/dx(sec⁻¹u)

Front

u'/|u|√(u²-1)

Back

Displacement of particle

Front

∫v(t)dt

Back

∫du/|u|√(u²-a²)

Front

(1/a)(sec⁻¹u/a)+C

Back

∫f(x)dx [BOUNDS ARE SAME]

Front

0

Back